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12 lines
306 B
Python
12 lines
306 B
Python
num_ore = 19
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mb_per_ore = 129
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mb_per_ingot = 144
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mb_per_coal = 144
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mb = num_ore * mb_per_ore
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num_ingots = int(mb / mb_per_ingot)
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num_coal = int(mb / mb_per_coal)
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lost_mb = mb % mb_per_ingot
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print(f"With {num_ore} ore and {num_coal} coal, you will get {num_ingots} ingots and lose {lost_mb} MB of iron.") |